ENGG 1015 Tutorial Circuit Analysis 5 Nov Learning Objectives News Analysis circuits through circuit laws (Ohms Law, KCL and KVL) HW1 deadline (5 Nov 23:55) Ack.: HKU ELEC1008 and MIT OCW 6.01 1 Quick Checking
NOT Always always True true R2 If R4 R3 , then i6 0 R5 i2 i3 i4 i5 i2 i6 i3 e1 R4
R2 R4 If i6 0, then R2 R2 R4 R3 V0 R3 R5 2 What is a Circuit? Circuits are connects of components Through which currents flow Across which voltages develop
3 Rules Governing Flow and Voltages Rule 1: Currents flow in loops Rule 2: Like the flow of water, the flow of electrical current (charged particles) is incompressible The same amount of current flows into the bulb (top path) and out of the bulb (bottom path) Kirchoffs Current Law (KCL): the sum of the currents into a node is zero Rule 3: Voltages accumulate in loops
Kirchoffs Voltage Law (KVL): the sum of the voltages around a closed loop is zero 4 Rules Governing Components Each component is represented by a relationship between the voltage (V) across the component to the current (I) through the component Ohms Law (V = IR) R: Resistance 5 Question 1: Current and Voltage
If R = 0 ohm, I1 = If R = 1 ohm, V1 = 6 Solution 1 If R = 0 ohm, I1 = 6V/3 ohm = 2A If R = 1 ohm, V1 6 V1 V1 5 0 V 3V 1 3 1 1 7 Parallel/Series Combinations
To simplify the circuit for analysis v R1i R2i Series v Rs i Rs R1 R2 Rp 1 1 R1 R1 // R2 1 R2 R1 R2 R1 R2 Parallel
8 Voltage/Current Divider Voltage Divider I V R1 R2 V1 R1 I R1 V R1 R2 V2 R2 I R2 V R1 R2 Current Divider
V R1 // R2 I I1 R2 V R1 // R2 I I R1 R1 R1 R2 I2 R1 I R1 R2 9 Question 2a: Voltage Calculation Find V2 using single loop analysis
Without simplifying the circuit Simplifying the circuit Vs1 2v, Vs 2 2v, Vs 3 2v, R1 1, R2 2, R3 4 Vs2 R1 Vs1 Vs3 R2 + R3 10 Solution 2a Choose loop current
Vs2 R1 Vs1 Vs3 Apply KVL R2 + R3 Replace V2 by R2I Vs 2 R1 I R2 I R3 I Vs 3 Vs1 0 2 I A 7
Find V2 4 V2 R2 I v 7 11 Solution 2b Simplify the circuit with one voltage source and one resistor Req. = R1 + R2 + R3 = 7 ohm Veq. = Vs1 + Vs2 + Vs3 = -2 + 2 + 2 = 2 V I = Veq. / Req. = 2/7 A
V2 = 4/7 v Veq. Req. 12 Question 3: Potential Difference Assume all resistors have the same resistance, R. Determine the voltage vAB. 13 Solution 3 Determine VAB
We assign VG=0 R2 VA 5 2.5V R1 R2 R4 VB 3 1.5V R3 R4 VAB VA VB 2.5 1.5 4V 14 Question 4: Current Calculation using Parallel/Series Combinations For the circuit in the figure, determine i1 to i5. 15 Solution 4 We apply:
(i) 3 4 40V 1 V = IR Series / Parallel Combinations Current Divider 2 (ii) 2 1 // 2
42 7 3 i3 11.2 1.6 9.6 A i3 i4 i5 i4 2 i5 3 9.6 6.4 A 1 9.6 3.2 A 3 17 Question 5: Resistance Calculation using Parallel/Series Combinations Find Req and io in the circuit of the figure. 18 Solution 5 (i)
20 60 Req Req 15 // 20 // 60 7.5 V IR 40 i0 7.5 5 i0 3.2 A 20 Analyzing Circuits
Assign node voltage variables to every node except ground (whose voltage is arbitrarily taken as zero) Assign component current variables to every component in the circuit Write one constructive relation for each component in terms of the component current variable and the component voltage Express KCL at each node except ground in terms of the component currents Solve the resulting equations Power = IV = I2R = V2/R 21 Question 6: Circuit Analysis (I) R1 = 80, R2 = 10, R3 = 20, R4 = 90, R5 = 100 Battery: V1 = 12V, V2 = 24V, V3 = 36V
Resistor: I1, I2, , I5 = ? P1, P2, , P5 = ? 22 Solution 6a VN = 0 I1: M R5 V1 R1 B I2: M V3 R3 R2 B I4: M V2 R4 B Step 1, Step 2
We have reviewed prepositions in 8 parts of speech. Definition: Preposition shows direction, location, or association. Prepositions . This is the next grammar unit. You will be. responsible for this information on your next quiz. Keepyour warm ups, and add...
COL with Courtney Yarholar- Suicide Prevention Resource Center- included Garrett Lee Smith Suicide Prevention grantees NCUIH 2014-15 Main Objectives Provide MSPI informational webinar/training to all Urban Indian Health Programs.
Electrode potential against hydrogen reference electrode. Indicating the electrode concentration in a solution. Both measures electrode potential with probes. Preliminary knowledge on a electrochemical cell required. oxidation state: charges on an ion, assuming a perfect ionic bonding. oxidation-reduction: Increase-decrease of...
Ready to download the document? Go ahead and hit continue!