Analysis of truss-Method of Joint Methods of Analysis Method of Joints The method of joints utilizes the force equations of equilibrium for each joint. Analysis normally begins at a joint where at least one force is known and not more than two forces are unknown for plane trusses (or not more than three forces are unknown for space trusses) Method of Sections The method of section has the basic advantage that the force in almost any desired member may be found directly from an analysis of a section which has cut the member. In choosing a section of the truss, in general, not more than three members
whose forces are unknown may be cut, since there are only three available equilibrium equations which are independent. 2 Problem -1 Compute the forces in all the members of the truss, shown here, using the method of joints. 2.4 m D C 2 kN 1.8 m A B
3 Support Reactions 2.4 m D C 2 kN 1.8 m Ax Support Reactions () Fx 0 Ax 2 0 Ax 2 kN A Ay
B By CCW ()M B 0 2 1.8 Ay 2.4 0 Ay 1.5 kN () Fy 0 Ay B y 0 B y 1.5 kN BD 1.82 2.4 2 3 m cos 2.4 / 3 0.8; sin 1.8 / 3 0.6 4 Calculation of the Member forces D 2 kN A 1.5 kN
C B 2 kN Note: For convenience, assume tension in all the members. Remember! A member in compression pushes on the joint and a member in tension pulls on the joint. 1.5 kN 5 Calculation of the Member forces BD 1.82 2.4 2 3 m
cos 2.4 / 3 0.8; sin 1.8 / 3 0.6 Member Forces D C 2 kN FAD Joint A 2 kN A 1.5 kN B
1.5 kN 2 kN A FAB 1.5 kN () Fx 0 FAB 2 0 FAB 2 kN(T) () Fy 0 FAD 1.5 0 FAD 1.5 kN(T) 6 Calculation of the Member forces D 2 kN A 1.5 kN C
2 kN B 1.5 kN Member Forces BD 1.82 2.4 2 3 m cos 2.4 / 3 0.8; sin 1.8 / 3 0.6 Joint B FBC FBD FBA 2 kN
() Fx 0 FBD cos 2 0 FBD 0.8 2 0 B 1.5 kN FBD 2.5 kN (C) () Fy 0 1.5 FBD sin FBC 0 1.5 2.5 0.6 FBC 0 FBC 0 7 Calculation of the Member forces D 2 kN A 1.5 kN
C B 1.5 kN 2 kN Member Forces Joint C BD 1.82 2.4 2 3 m cos 2.4 / 3 0.8; sin 1.8 / 3 0.6 FCD C
2 kN FCB 0 () Fx 0 2 FCD 0 FCD 2 kN (T) 8 Member forces Member L (m) Forces (kN) Nature AB 2.4
2.0 Tension BC 1.8 0.0 - CD 2.4 2.0 Tension DA
1.8 1.5 Tension BD 3.0 -2.5 Compression 9 Example 1: Method of Joints Plane Truss 6 - 10
ENGINEERING MECHANICS : STATICS Example 1 (continued): Alternatively, Fx=0 and Fy=0 will give the same results Alternatively, Fx=0 and Fy=0 will give the same results 6 - 11 ENGINEERING MECHANICS : STATICS Example 1 (continued): 6 - 12 Example 1 (continued): 6 - 13 Zero Force Members Case 1: If only two
non-collinear members form a truss joint and no external load or support reaction is acting at the joint, the members must be zero force members. D C BC and CD are zero force members. A B WHY ????? 02/26/2020 14
Zero Force Members (Contd.) Case 2: If there is an external load at the joint, where two members are meeting, and it is acting in the direction of one of the members, another member will be a zero force member. D C 2 kN BC is a zero force members. Ax A WHY ?????
Ay 02/26/2020 B By 15 Zero Force Members (Contd.) Case 3: If three members form a truss joint for which two of the members are collinear, the third member is a zero force member provided no external force or support reaction is acting at the joint. C G F
A B D 02/26/2020 EF is a zero force member. E WHY ????? 16 ENGINEERING MECHANICS : STATICS Zero-Force Members ! Zero-force members are used to increase the stability and rigidity of the truss and to provide support for various loading
conditions as well as to support the weight of the truss and to maintain the truss in the desired shape. Although they carry no load, they prevent structural collapse. 6 - 17 Problem-2 Identify zero force members in a truss shown. Answer: BH and DF are zero force members. 02/26/2020 18 Problem-3 For the truss shown in the Figure, identify all correct zero-force members.
J 60 kN I H G F 5m A C D E B
5m 02/26/2020 5m 40 kN 5m 5m 19 Solution 60 kN J I H G
F 5m A C D E B 5m 5m 40 kN 5m 5m
AB and AJ are zero-force members. JB, JI and IH are also zero-force members. CH is a zero-force member GD is a zero-force member ED is a zero-force member 02/26/2020 20 Example 2: Zero-Force Members For the given loading, determine the zero-force members in the truss shown. 6 - 21 Example 3: Zero-Force Members For the given loading, determine the zero-force members in the truss shown. 6 - 22
Example 4: Zero-Force Members For the given loading, determine the zero-force members in the truss shown. 6 - 23 Example 5: Zero-Force Members For the given loading, determine the zero-force members in the truss shown. 6 - 24
Best fit: mencari di seluruh list DMB yg paling sesuai dng kebutuhan proses Worst fit: mencari di seluruh list DMB yg paling besar yg tersedia Manajemen Memori Pelacakan memori bebas dengan metode buddy system Berdasar kenyataan bhw komputer bekerja dng...
*Uptake of X-gal and IPTG controlled by Lac Permease *Small amount of Lac Permease present in membrane at all times *IPTG not degraded. Wild type. Media with ONPG, toluene, + IPTG. Media with ONPG, toluene, - IPTG *X-gal and IPTG...
"The Essence of Love" Two Things: Love is a Concept Abstract Types of Definitions: Real Nominal Operational Error/Bias Composite Measure Index Scale Index Sum or Average of Scores Political Involvement Political Involvement Scale Unidimensionality Same Score Different Responses Assign Scores...
Delimiters. The <br /> (newline) (carriage return) is a very important symbol in text files. It delimits what Python calls a 'line' in the file. It gets put into the file whenever you press Enter at the end of a...
Arlington's Environmental Statistics will be rolled into this annual report. Capital Power has a unique leading edge Key Performance Indicator Program that affects all personnel at Capital Power. Every employee at Capital Power from the CEO to the mail clerk...
a 5 b c 4 3 2 1 Path from evidence generation to clinical application Steps: 1. generation of evidence from research; 2. evidence summary and synthesis; 3. forming clinical policy; 4. application of policy; 5. individual clinical decisions, including...
Ready to download the document? Go ahead and hit continue!